三维数组模板类

C:很难蒙混过关的CArray3d三维数组模板类

总时间限制: 1000ms 内存限制: 65536kB

描述

实现一个三维数组模版CArray3D,可以用来生成元素为任意类型变量的三维数组,输出指定结果

#include <iostream>
#include <iomanip> 
#include <cstring>
using namespace std;
template <class T>
class CArray3D
{
// 在此处补充你的代码
};

CArray3D<int> a(3,4,5);
CArray3D<double> b(3,2,2);
void PrintA()
{
	for(int i = 0;i < 3; ++i) {
		cout << "layer " << i << ":" << endl;
		for(int j = 0; j < 4; ++j) {
			for(int k = 0; k < 5; ++k) 
				cout << a[i][j][k] << "," ;
			cout << endl;
		}
	}
}
void PrintB()
{
	for(int i = 0;i < 3; ++i) {
		cout << "layer " << i << ":" << endl;
		for(int j = 0; j < 2; ++j) {
			for(int k = 0; k < 2; ++k) 
				cout << b[i][j][k] << "," ;
			cout << endl;
		}
	}
}

int main()
{

	int No = 0;
	for( int i = 0; i < 3; ++ i ) {
		a[i];
		for( int j = 0; j < 4; ++j ) {
			a[j][i];
			for( int k = 0; k < 5; ++k )
				a[i][j][k] = No ++;
			a[j][i][i];	
		}
	}
	PrintA();
	memset(a[1],-1 ,20*sizeof(int));	
	memset(a[1],-1 ,20*sizeof(int));
	PrintA(); 
	memset(a[1][1],0 ,5*sizeof(int));	
	PrintA();

	for( int i = 0; i < 3; ++ i )
		for( int j = 0; j < 2; ++j )
			for( int k = 0; k < 2; ++k )
				b[i][j][k] = 10.0/(i+j+k+1);
	PrintB();
	int n = a[0][1][2];
	double f = b[0][1][1];
	cout << "****" << endl;
	cout << n << "," << f << endl;
		
	return 0;
}

输入

输出

等同于样例

样例输入

样例输出

layer 0:
0,1,2,3,4,
5,6,7,8,9,
10,11,12,13,14,
15,16,17,18,19,
layer 1:
20,21,22,23,24,
25,26,27,28,29,
30,31,32,33,34,
35,36,37,38,39,
layer 2:
40,41,42,43,44,
45,46,47,48,49,
50,51,52,53,54,
55,56,57,58,59,
layer 0:
0,1,2,3,4,
5,6,7,8,9,
10,11,12,13,14,
15,16,17,18,19,
layer 1:
-1,-1,-1,-1,-1,
-1,-1,-1,-1,-1,
-1,-1,-1,-1,-1,
-1,-1,-1,-1,-1,
layer 2:
40,41,42,43,44,
45,46,47,48,49,
50,51,52,53,54,
55,56,57,58,59,
layer 0:
0,1,2,3,4,
5,6,7,8,9,
10,11,12,13,14,
15,16,17,18,19,
layer 1:
-1,-1,-1,-1,-1,
0,0,0,0,0,
-1,-1,-1,-1,-1,
-1,-1,-1,-1,-1,
layer 2:
40,41,42,43,44,
45,46,47,48,49,
50,51,52,53,54,
55,56,57,58,59,
layer 0:
10,5,
5,3.33333,
layer 1:
5,3.33333,
3.33333,2.5,
layer 2:
3.33333,2.5,
2.5,2,
****
7,3.33333

提示建议做法:
1. a[i][j][k] 这个表达式的第一个[]返回一个内部类的对象,该内部类也重载了[],且返回值为指针。
2. 必要时需重载对象到指针的强制类型转换运算符

来源Guo Wei

主要问题在于需要内存连续且多重【】访问
所以我们在class里内建类,并新建一维数组

注意重定义一下类型转换函数T* (memset用)

#include <iostream>
#include <iomanip> 
#include <cstring>
#include<string>
#include<cstdio>
#include<algorithm>
using namespace std;
template <class T>
class CArray3D
{
    class CArray2D{
        T *p;
        int b,c;
    public:
        CArray2D(){p=new T[1];}
        ~CArray2D(){
            delete [] p;
        }
        void INIT(int _b,int _c){
            b=_b;c=_c;
            delete [] p;
            p=new T[b*c+1];
        }
        T* operator [](int x){
            return p+c*x;
        }
        operator T*(){
            return p;
        }
    };
public:
    CArray2D *p;
    CArray3D(int a,int b,int c){
        p=new CArray2D[a];
        for(int i=0;i<a;++i) p[i].INIT(b,c);
    }
    ~CArray3D(){
        delete [] p;
    }
    CArray2D& operator [](int x){
        return p[x];
    }
// 在此处补充你的代码
};

CArray3D<int> a(3,4,5);
CArray3D<double> b(3,2,2);
void PrintA()
{
	for(int i = 0;i < 3; ++i) {
		cout << "layer " << i << ":" << endl;
		for(int j = 0; j < 4; ++j) {
			for(int k = 0; k < 5; ++k) 
				cout << a[i][j][k] << "," ;
			cout << endl;
		}
	}
}
void PrintB()
{
	for(int i = 0;i < 3; ++i) {
		cout << "layer " << i << ":" << endl;
		for(int j = 0; j < 2; ++j) {
			for(int k = 0; k < 2; ++k) 
				cout << b[i][j][k] << "," ;
			cout << endl;
		}
	}
}

int main()
{

	int No = 0;
	for( int i = 0; i < 3; ++ i ) {
		a[i];
		for( int j = 0; j < 4; ++j ) {
			a[j][i];
			for( int k = 0; k < 5; ++k )
				a[i][j][k] = No ++;
			a[j][i][i];	
		}
	}
	PrintA();
	memset(a[1],-1 ,20*sizeof(int));	
	memset(a[1],-1 ,20*sizeof(int));
	PrintA(); 
	memset(a[1][1],0 ,5*sizeof(int));	
	PrintA();

	for( int i = 0; i < 3; ++ i )
		for( int j = 0; j < 2; ++j )
			for( int k = 0; k < 2; ++k )
				b[i][j][k] = 10.0/(i+j+k+1);
	PrintB();
	int n = a[0][1][2];
	double f = b[0][1][1];
	cout << "****" << endl;
	cout << n << "," << f << endl;
		
	return 0;
}

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